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h ctatk fr imackgrfamily: 宋体;usNne-eeryt 2 2low:/re >前天下午,在重庆南坪一个k" У淖裳嵘希碧傅絯" 战略规划与项目定位时,我有了对一根绳子的思4。我说,同样是一根绳子,如果套在脖子上就是自寻死路,如果拿在手上就会多了活法。于是,关于绳子的思4由此展开。an cta>anp> h ctatspagogEN-US/re >qbbkdban cta>aw?fxfblog.1由绳子引发的思4 - 高扬 - 高扬.知识解决.ank"/re al ="由绳子引发的思4 - 高扬 - 高扬.知识解决.ank"/re ing'"">hnp>"jximfblog.1由绳子引发的思4 - 高扬 - 高扬.知识解决.ank"/re al ="由绳子引发的思4 - 高扬 - 高扬.知识解决.ank"/re ing'"">

h ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >先说下猪朋狗友的段子。有一天狗掉进枯井里,猪在上面急得团团转,狗对猪说:“你去找一个绳子让我抓住绳子的一头,就可以出去了。”谁叫咱们是 呢?猪很听狗的话,好不容易找来了一根绳子,正当狗感激涕零的时候,扑通一声,猪跳了下来,并拿着绳子的一头对狗说:“快抓住,你先上去,不用管我。”an cta>anp>

h ctatk fr imsNne-eeryt 2 2low:/re >qbbkdban cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >虽然思路决定出路,但即使有一个好创意,如果执行不到位一样救不了你。由此我又想到了在an cta>a ctatspagogEN-US/re >ss=2an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >年广东省an>< ctatspagogEN-US/re >ACMan cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >大赛试题中,甲乙两人之间进行的“割绳游戏”。an cta>anp>

h ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >从甲开始,两人轮流先切割再丢弃一段绳子。设有an>< ctatspagogEN-US/re >Nan cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >根长度都是整数的绳子,每根长度已知,每人每次丢弃绳子的长度也必须是整数,不得超过an cta>a ctatspagogEN-US/re >Man cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re > clΩ檬窍率鋈智榭鲋唬篴n> ctatspagogEN-US/re >
1an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily: Cambria;/re >、丢弃整根绳子;an cta>a ctatspagogEN-US/re >
2an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily: Cambria;/re >、切割一根绳子为二段,丢弃其中一段;an cta>a ctatspagogEN-US/re >
3an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily: Cambria;/re >、切割一根绳子为三段,丢弃中间的那一段;能够取到最后一段绳子并丢弃者胜,也就是最先出现无绳可取者负。an cta>anp>

h ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >这是一个开始就可以确定胜负的游戏,你的任务就是编写判断胜负的程序。对程序的输入是an cta>a ctatspagogEN-US/re >Nan cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re > can cta>a ctatspagogEN-US/re >Man cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,及an cta>a ctatspagogEN-US/re >Nan cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >根绳子的长度an cta>a ctatspagogEN-US/re >X1an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,an cta>a ctatspagogEN-US/re >X2an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re > c……,of cta>a ctatspagogEN-US/re >XNan cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,输出谁是胜者,即甲胜输出甲,乙胜输出乙。做为课程设计题目,还要求你说明取胜者的取胜操作策略。你的程序lΩ迷市韔f cta>a ctatspagogEN-US/re > 1≤N≤pa>of cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily: Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >1≤Man cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >、an>< ctatspagogEN-US/re >Xi≤pa>>of cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >。an cta>a ctatspagogEN-US/re >
of cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily: Cambria;/re >三个样例如下:an> ctatspagogEN-US/re >
"jximfblog.1由绳子引发的思4 - 高扬 - 高扬.知识解决.ank"/re al ="由绳子引发的思4 - 高扬 - 高扬.知识解决.ank"/re ing'"">h ctatk fr imsNne-eeryt 2 2low: ackgrfamily: 宋体;/re >of cta>1an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily: Cambria;/re >、输入of cta>a ctatspagogEN-US/re > 1an cta>a ctatk fr imackgrfamily:宋体; mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >2an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re > cof cta>a ctatspagogEN-US/re >9an>< ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,则lκ涑黾资ぃ挥幸桓f cta>a ctatspagogEN-US/re >9an>< ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >的绳子,每次丢弃不能超过an cta>a ctatspagogEN-US/re >2an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,甲可以割三段丢弃中间长of cta>a ctatspagogEN-US/re >1an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >的一段,留长都为of cta>a ctatspagogEN-US/re >4of cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >的两段,然后乙在一根绳子上怎样做,甲只需对另一根绳子照办,必可以取到最后一段。an cta>a ctatspagogEN-US/re >
2an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily: Cambria;/re >、输入of cta>a ctatspagogEN-US/re >3an cta>a ctatk fr imackgrfamily:宋体; mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >1>of cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >3an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >5of cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >6of cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,输出乙胜。an cta>a ctatspagogEN-US/re >anp>

h ctatspagogEN-US/re >3an cta>a ctatk fr imackgrfamily:宋体; mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >、输入of cta>a ctatspagogEN-US/re >3an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >2an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >3an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >5of cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >,of cta>a ctatspagogEN-US/re >6of cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >,输出甲胜。an cta>anp>"p>h ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily: Cambria;/re >有趣的是,如果不看丢弃绳子的第an cta>a ctatspagogEN-US/re >3an cta>a ctatk fr imackgrfamily: 宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >种情况,本题就是经典的“取石子游戏”。即有两堆石子,数量任意,可以不同。游戏开始由两个人轮流取石子。游戏规定,每次有两种不同的取法,一是可以在任意的一堆中取走任意多的石子;二是可以在两堆中同时取走相同数量的石子。最后把石子全部取完者为胜者。现在给出初始的两堆石子的数目,如果轮到你先取,假设双方都采取最好的策略,问最后你是胜者还是败者。of cta>anp>"ay:6h ctatk fr imsNne-eeryt 2 2low: ackgrfamily: 宋体;/re >先暂不讨论如何应对程序设计问题,我想说的是思路。创新总在跨界处,因为越是专业的问题,越是阻碍专家的创新。绳子不仅给我带来了创意思4,还带来了人生思4。同样也是一根绳子的故事,它折射出不同的人生哲学。of cta>a ctatk fr imsNne-eeryt 2 2low:/re >qbbkdban cta>as="fl 三个好兄弟一同掉进了深深的枯井里,在生命垂危之际,施救者放下一根绳子,他们三人同时抓住了绳子向上攀爬。当爬到井下一半时,上面有人说了:“绳子只能承受两个人的重量,否则就会崩断,三个人面面相视,过了片刻,其中一个人松开了手,他掉下去,把生的希望留给了两个兄弟。of cta>anp>

h ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria; mso-ndesi-ackgrfamily:Cambria;/re >剩下的两个人眼里流着泪继续往上爬,爬到井口距离of cta>a ctatspagogEN-US/re >1/3an cta>a ctatk fr imackgrfamily:宋体;mso-ascii-ackgrfamily:Cambria;mso-ndesi-ackgrfamily:Cambria;/re >的时候,上面又有人说:“绳子只能承受一个人的重量,否则就会有绷断。”只见两个人紧紧抓住绳子,他们互相对视着。在离生只有几步之遥的时候,谁也不愿意松手。过了好久,其中一个人果断地伸出脚,把另一个人踹了下去。of cta>anp>"ay:6hay:nk fr imef="/t="gn: cigter:/re >hw?fxfblog.1由绳子引发的思4 - 高扬 - 高扬.知识解决.ank"/re al ="由绳子引发的思4 - 高扬 - 高扬.知识解决.ank"/re inyle="a" hre: .har .p;3')oat: edne:/re ing'"">qbbkdban cta>a ctatk fr imsNne-eeryt 2 2low: ef="/t="gn: /spa:/re >qbbkdban cta>as="fl萻="fl 哲学家说,第一个虽然死了,却还活着;第三个人活着,但却已经死了。佛学家说,放手即是得到,第一个人虽然松开了绳子,得到了升华,第三个人抓住了绳子,却最终堕落。在大众眼里,第一个人升入了天堂,第二个人进入了坟墓,第三个人下 cl狱。现实生活中,第一个,第二个人死了,第三个人最终爬了上去。of cta>a ctatspagogEN-US/re >anp>

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